EMC E10-001 Online Practice Questions and Exam Preparation

EMC E10-001 Online Questions & Answers

• Question 71:

  An organization plans to deploy a new business application in their environment. The new application requires 2 TB of storage space. During peak workloads, the application is expected to generate 9,800 IOPS with a typical I/O size of 4 KB. Because the application is business-critical, the response time must be within acceptable range.

  The available disk drive option is a 15,000 rpm drive with 100 GB capacity. The number of IOPS in which the disk drive can perform at 100 percent utilization is 140.

  What is the number of disk drives needed to meet the application's capacity and performance requirements?

  A. 20
  B. 60
  C. 70
  D. 100
  D. 100

• Question 72:

  What is a function of the policy engine in inter-array storage tiering?

  A. Facilitates moving inactive data from primary to secondary storage
  B. Creates a stub file in secondary storage pointing to data on the primary storage
  C. Ensures that primary and secondary storage have identical data for compliance
  D. Runs backup agent and determines the files to be copied to the secondary storage
  A. Facilitates moving inactive data from primary to secondary storage

• Question 73:

  What should be considered when determining the recovery point objective (RPO) in a log shipping remote replication?

  A. Frequency of log switching
  B. Size of the source database
  C. Size of the standby database
  D. Frequency of reading the database
  A. Frequency of log switching

• Question 74:

  Which feature(s) ensures that the stored content has NOT been altered in a CAS system?

  A. Single instance storage
  B. Content integrity
  C. Content mirroring and parity protection
  D. Location independence
  B. Content integrity

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  Key features of CAS

  CAS provides all the features required for storing fixed content. The key features of CAS are as follows:

  Content authenticity: It assures the genuineness of stored content. This is achieved by generating a unique content address for each object and validating the content address for stored objects at regular intervals. Content authenticity is

  assured because the address assigned to each object is as unique as a fingerprint. Every time an object is read, CAS uses a hashing algorithm to recalculate the object's content address as a validation step and compares the result to its

  original content address. If the object fails validation, CAS rebuilds the object using a mirror or parity protection scheme.

  Content integrity: It provides assurance that the stored content has not been altered. CAS uses a hashing algorithm for content authenticity and integrity. If the fixed content is altered, CAS generates a new address for the altered content,

  rather than overwrite the original fixed content.

  Location independence: CAS uses a unique content address, rather than directory path names or URLs, to retrieve data. This makes the physical location of the stored data irrelevant to the application that requests the data.

  Single-instance storage (SIS): CAS uses a unique content address to guarantee the storage of only a single instance of an object. When a new object is written, the CAS system is polled to see whether an object is already available with the

  same content address. If the object is available in the system, it is not stored; instead, only a pointer to that object is created.

  Retention enforcement: Protecting and retaining objects is a core requirement of an archive storage system. After an object is stored in the CAS system and the retention policy is defined, CAS does not make the object available for deletion

  until the policy expires.

  Data protection: CAS ensures that the content stored on the CAS system is available even if a disk or a node fails. CAS provides both local and remote protection to the data objects stored on it. In the local protection option, data objects are

  either mirrored or parity protected. In mirror protection, two copies of the data object are stored on two different nodes in the same cluster. This decreases the total available capacity by 50 percent. In parity protection, the data object is split in

  multiple parts and parity is generated from them.

  Each part of the data and its parity are stored on a different node. This method consumes less capacity to protect the stored data, but takes slightly longer to regenerate the data if corruption of data occurs. In the remote replication option,

  data objects are copied to a secondary CAS at the remote location. In this case, the objects remain accessible from the secondary CAS if the primary CAS system fails.

  Fast record retrieval: CAS stores all objects on disks, which provides faster access to the objects compared to tapes and optical discs.

  Load balancing: CAS distributes objects across multiple nodes to provide maximum throughput and availability.

  Scalability: CAS allows the addition of more nodes to the cluster without any interruption to data access and with minimum administrative overhead. ?Event notification: CAS continuously monitors the state of the system and raises an alert for

  any event that requires the administrator's attention. The event notification is communicated to the administrator through SNMP, SMTP, or e-mail. Self diagnosis and repair: CAS automatically detects and repairs corrupted objects and alerts

  the administrator about the potential problem. CAS systems can be configured to alert remote support teams who can diagnose and repair the system remotely. ?Audit trails: CAS keeps track of management activities and any access or

  disposition of data. Audit trails are mandated by compliance requirements. EMC E10-001 Student Resource Guide. Module 8: Object-based and Unified Storage

• Question 75:

  Which aspect of a business continuity solution is determined by the recovery point objective?

  A. Frequency of backup
  B. Type of backup devices
  C. Type of disaster recovery site
  D. Choice of backup software
  A. Frequency of backup

• Question 76:

  What is an accurate statement about a software RAID implementation?

  A. Uses host CPU cycles to perform RAID calculations
  B. Supports the upgrade of RAID software on incompatible O/S
  C. Uses a specialized hardware controller to perform RAID calculations
  D. Supports all RAID levels
  A. Uses host CPU cycles to perform RAID calculations

• Question 77:

  What is a logical component of a storage environment?

  A. Bus
  B. Disk
  C. Filesystem
  D. Memory
  C. Filesystem

• Question 78:

  What is a sequence' in a Fibre Channel (FC) data structure?

  A. Group of exchanges that are sent to another port to perform certain operations
  B. Contiguous set of information units that map to a frame header
  C. Upper layer protocol-specific information in a FC frame
  D. Contiguous set of frames that correspond to an information unit
  D. Contiguous set of frames that correspond to an information unit

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  Structure and Organization of FC Data

  

  In an FC network, data transport is analogous to a conversation between two people, whereby a frame represents a word, a sequence represents a sentence, and an exchange represents a conversation.

  Exchange: An exchange operation enables two node ports to identify and manage a set of information units. Each upper layer protocol has its protocol-specific information that must be sent to another port to perform certain operations. This protocol-specific information is called an information unit. The structure of these information units is defined in the FC-4 layer. This unit maps to a sequence. An exchange is composed of one or more sequences. Sequence: A sequence refers to a contiguous set of frames that are sent from one port to another. A sequence corresponds to an information unit, as defined by the ULP.

  Frame: A frame is the fundamental unit of data transfer at Layer 2. An FC frame consists of five parts: start of frame (SOF), frame header, data field, cyclic redundancy check (CRC), and end of frame (EOF). The SOF and EOF act as delimiters. The frame header is 24 bytes long and contains addressing information for the frame. The data field in an FC frame contains the data payload, up to 2,112 bytes of actual data--in most cases, the SCSI data. The CRC checksum facilitates error detection for the content of the frame. This checksum verifies data integrity by checking whether the content of the frames was received correctly. The CRC checksum is calculated by the sender before encoding at the FC-1 layer. Similarly, it is calculated by the receiver after decoding at the FC-1 layer. EMC E10-001 Student Resource Guide. Module 5: Fibre Channel Storage Area Network (FC SAN)

• Question 79:

  What is prevented using RAID technology?

  A. Data loss
  B. Host Bus Adapter failures
  C. Security breach
  D. Switch failure
  A. Data loss

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  Today's data centers house hundreds of disk drives in their storage infrastructure. Disk drives are inherently susceptible to failures due to mechanical wear and tear and other environmental factors, which could result in data loss. The greater the number of disk drives in a storage array, the greater the probability of a disk failure in the array. For example, consider a storage array of 100 disk drives, each with an average life expectancy of 750,000 hours. The average life expectancy of this collection in the array, therefore, is 750,000/100 or 7,500 hours. This means that a disk drive in this array is likely to fail at least once in 7,500 hours. RAID is an enabling technology that leverages multiple drives as part of a set that provides data protection against drive failures. In general, RAID implementations also improve the storage system performance by serving I/Os from multiple disks simultaneously. Modern arrays with flash drives also benefit in terms of protection and performance by using RAID.

  EMC E10-001 Student Resource Guide. Module 3: Data Protection - RAID

• Question 80:

  When deploying a cold backup solution, what should be considered?

  A. Application must be shut down during the backup process
  B. Application can only read the data to be backed up
  C. An open file agent must be deployed to perform the backup
  D. Deduplication cannot be performed during the backup process
  A. Application must be shut down during the backup process