Test Prep OAT Online Practice Questions and Exam Preparation

Test Prep OAT Online Questions & Answers

• Question 171:

  A woman is holding a 2 lb ball 3 feet above her head. How much work is the woman doing to keep the object above her head?

  A. 0 ft lb
  B. 3/2 ft lb
  C. 6 ft lb
  D. 12 ft lb
  E. Cannot be determined without more information.
  A. 0 ft lb

  ---

  Given too much information when knowing the concept behind `work' is all that is needed to be solved.

  Because the ball is held above the woman's head and is not moving, the woman is not doing any work at all. There is no displacement, and thus, work amounts to 0.

• Question 172:

  What is the pH of 0.001M NaOH solution?

  A. 11
  B. 3
  C. 13
  D. 8
  E. 5
  A. 11

  ---

  Because this is a strong base, we automatically assume concentration of [OH−] = 0.001 = 1.0 × 10−3.

  pOH = −log[OH−] = −log[1.0 × 10−3] = −(−3) = 3 pH = 14 − pOH pH = 14 − 3 = 11

  Be sure to be familiar and able to calculate logs. You will be expected to without a calculator. The above problem was an easy conversion (likely to be seen), but you may provided with more harder ones (ex. [OH−] = 3.4 × 10−3)

• Question 173:

  Chlorophyll is associated with which of the following metals?

  A. Zinc
  B. Iron
  C. Magnesium
  D. Silver
  E. Manganese
  C. Magnesium

  ---

  Chlorophyll has a central magnesium atom associated with it (whereas hemoglobin has iron).

• Question 174:

  What is the average of: 15, 25%, 1/2 and sin0?

  A. 3.02
  B. 3.94
  C. 4.20
  D. 4.64
  E. 5.21
  B. 3.94

  ---

  The important part is to do these as quick as possible to leave room for the lengthier QR problems. Simply convert the numbers to 15, 0.25, 0.5 and 0. Add them up and divide by 4 to find the average.

• Question 175:

  Which algebraic expression best represents the following statement: the number of books Brian read over the summer (B) is 2 less than 3 times the number of books his brother Adam read over the summer (A)?

  A. B = 3A - 2
  B. B = 3A + 2
  C. A = 3B - 2
  D. A = 3B + 2
  A. B = 3A - 2

• Question 176:

  For the following nuclear reaction, fill in the correct daughter product.

  

  A. Option A
  B. Option B
  C. Option C
  D. Option D
  E. Option E
  A. Option A

  ---

  Begin by looking at the reactant side and noting down the number of mass number and protons (235 and 92 respectively). These numbers have to match the total numbers on the product side. The 2 alpha-decay and 1 beta-decay give you a mass of 8, which means it is 227 short of the mass number in the reactants. They also produce a (2 + 2 − 1 = 3) number of protons, 89 short of balancing the reactant number of protons. Thus, your missing daughter nuclei will have a mass of 227 and 89 protons. Looking at a periodic table, the atom Ac has 89 protons.

• Question 177:

  What is the hydrostatic pressure in a pond at a depth of 100 m? (Density of water = 1000 kg/m3)

  A. 1.0 × 106 Pa
  B. 1.0 × 106 atm
  C. 1.0 × 105 Pa
  D. 1.0 × 105 atm
  E. 300 Pa
  A. 1.0 × 106 Pa

  ---

  Hydrostatic Pressure = gD where:

  = Density of fluid (1000 kg/m?here, as given) g = Gravity (unless stated otherwise, this is 10 m/s? D = Depth (100 m, as given)

  Simply plug and chug. Remember the SI unit of pressure is Pascal (Pa). Since all given units are in their respective SI formats, no conversion is needed.

• Question 178:

  For the following reaction, which is a possible reagent that can be used to attain this product?

  

  A. 1) H4N2 / H2O 2) KOH / N2
  B. Zn (Hg) / HCl, heat
  C. Br2, NaOH, H2O / heat
  D. H2 / Pt
  E. None of the above
  C. Br2, NaOH, H2O / heat

  ---

  This is a Hofmann rearrangement reaction which converts a primary amide to a primary amine. Note the loss of the carbon.

• Question 179:

  This figure represents the score range for 520 students who took the OAT. How many students scored 360 or more points?

  

  A. 52
  B. 104
  C. 130
  D. 234
  E. 240
  A. 52

  ---

  If 10% of test takers got a 360+ score, then find 10% of 520.

  0.10 × 520 = 52

• Question 180:

  What is the sum of the interior angles of a regular nonagon?

  A. 900°
  B. 1080°
  C. 540°
  D. 1260°
  E. 1440°
  D. 1260°

  ---

  The sum of interior angles for any regular shaped polygon can be determined with the following equation:

  (n − 2) × 180°

  Where n is # of sides. In this case, a nonagon is a 9-sided polygon. Plugging in 9 in the equation gives 1260° for all 9 sides combined. If asked for EACH angle, then you would just divide 1260° by 9.