LSAC LSAT-TEST Online Practice Questions and Exam Preparation

LSAC LSAT-TEST Online Questions & Answers

• Question 281:

  Exactly seven toy-truck models ?F, G, H, J, K, M, and S ?are assembled on seven assembly lines, exactly one model to a line. The seven lines are arranged side by side and numbered consecutively F through 7. Assignment of models to

  lines must meet the following conditions:

  F is assembled on a lower-numbered line than J.

  M is assembled on the line numbered one lower than the line on which G is assembled.

  H is assembled on line 1 or else line 7.

  S is assembled on line 4.

  If M is assembled on line 1, which one of the following could be true?

  A. F is assembled on a line numbered one lower than the line on which H is assembled.
  B. F is assembled on a line numbered one lower than the line on which K is assembled.
  C. G is assembled on a line numbered one lower than the line on which J is assembled.
  D. G is assembled on a line numbered one lower than the line on which K is assembled.
  E. K is assembled on a line numbered one lower than the line on which G is assembled.
  D. G is assembled on a line numbered one lower than the line on which K is assembled.

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  Again, we're presented with a hypothetical piece of information which we need to incorporate into our sketch. If M is in1, then G must be in 2 (Rule 2), and H must be in 7 (Rule 3). We're left to place F, J, and K in accordance with Rule 1.

• Question 282:

  In 1892 the Sierra Club was formed. In 1908 an area of coastal redwood trees north of San Francisco was established as Muir Woods National Monument. In the Sierra Nevada mountains, a walking trail from Yosemite Valley to Mount Whitney was dedicated in 1938. It is called John Muir Trail. John Muir was born in 1838 in Scotland. His family name means "moor," which is a meadow full of flowers and animals. John loved nature from the time he was small. He also liked to climb rocky cliffs and walls. When John was eleven, his family moved to the United States and settled in Wisconsin. John was good with tools and soon became an inventor. He first invented a model of a sawmill. Later he invented an alarm clock that would cause the sleeping person to be tipped out of bed when the timer sounded. Muir left home at an early age. He took a thousand-mile walk south to the Gulf of Mexico in 1867and 1868. Then he sailed for San Francisco. The city was too noisy and crowded for Muir, so he headed inland for the Sierra Nevadas. When Muir discovered the Yosemite Valley in the Sierra Nevadas, it was as if he had come home. He loved the mountains, the wildlife, and the trees. He climbed the mountains and even climbed trees during thunderstorms in order to get closer to the wind. He put forth the theory in the late 1860's that the Yosemite Valley had been formed through the action of glaciers. People ridiculed him. Not until 1930 was Muir's theory proven correct. Muir began to write articles about the Yosemite Valley to tell readers about its beauty. His writing also warned people that Yosemite was in danger from timber mining and sheep ranching interests. In 1901 Theodore Roosevelt became president of the United States. He was interested in conservation. Muir took the president through Yosemite, and Roosevelt helped get legislation passed to create Yosemite National Park in 1906. Although Muir won many conservation battles, he lost a major one. He fought to save the Hetch Valley, which people wanted to dam in order to provide water for San Francisco. In the late 1913 a bill was signed to dam the valley. Muir died in 1914. Some people say losing the fight to protect the valley killed Muir.

  What did John Muir do soon after he arrived in San Francisco?

  A. He ran outside during an earthquake.
  B. He put forth a theory about how Yosemite was formed.
  C. He headed inland for the Sierra Nevadas.
  D. He began to write articles about the Sierra Nevadas.
  E. He wrote short stories for the local newspaper.
  C. He headed inland for the Sierra Nevadas.

• Question 283:

  Two men, Barry and David, and two women Ann and Cathy are doctors. One is a surgeon, one a dentist, one an optometrist, and one is a general practitioner. They are seated around a square table, with one person on each side.

  1) Barry is across from the dentist.

  2) David is not across from the surgeon.

  3) The optometrist is on Ann's immediate left.

  4) Cathy is the general practitioner.

  5) The surgeon and general practitioner are married to each other.

  6) The general practitioner is not on Cathy's immediate left.

  7) The general practitioner is across from the optometrist.

  Which of the following must be true?

  A. Barry is the dentist.
  B. The surgeon and general practitioner are women.
  C. The dentist is across from the surgeon.
  D. David is the surgeon.
  E. Cathy is across from Ann.
  C. The dentist is across from the surgeon.

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  Statement 7 tells you that the general practitioner is across from the optometrist. Therefore, the dentist must be across from the surgeon.

• Question 284:

  Philosopher Denise Meyerson views the Critical Legal Studies (CLS) movement as seeking to debunk orthodox legal theory by exposing its contradictions. However, Meyerson argues that CLS proponents tend to see contradictions where none exist, and that CLS overrates the threat that conflict poses to orthodox legal theory.

  According to Meyerson, CLS proponents hold that the existence of conflicting values in the law implies the absence of any uniquely right solution to legal cases. CLS argues that these conflicting values generate equally plausible but opposing answers to any given legal question, and, consequently, that the choice between the conflicting answers must necessarily be arbitrary or irrational. Meyerson denies that the existence of conflicting values makes a case irresolvable, and asserts that at least some such cases can be resolved by ranking the conflicting values. For example, a lawyer's obligation to preserve a client's confidences may entail harming other parties, thus violating moral principle. This conflict can be resolved if it can be shown that in certain cases the professional obligation overrides ordinary moral obligations.

  In addition, says Meyerson, even when the two solutions are equally compelling, it does not follow that the choice between them must be irrational. On the contrary, a solution that is not rationally required need not be unreasonable. Meyerson concurs with another critic that instead of concentrating on the choice between two compelling alternatives, we should rather reflect on the difference between both of these answers on the one hand, and some utterly unreasonable answer on the other ?such as deciding a property dispute on the basis of which claimant is louder. The acknowledgment that conflicting values can exist, then, does not have the far-reaching implications imputed by CLS; even if some answer to a problem is not the only answer, opting for it can still be reasonable.

  Last, Meyerson takes issue with the CLS charge that legal formalism, the belief that there is a quasi-deductive method capable of giving solutions to problems of legal choice, requires objectivism, the belief that the legal process has moral authority. Meyerson claims that showing the law to be unambiguous does not demonstrate its legitimacy: consider a game in which participants compete to steal the item of highest value from a shop; while a person may easily identify the winner in terms of the rules, it does not follow that the person endorses the rules of the game. A CLS scholar might object that legal cases are unlike games, in that one cannot merely apply the rules without appealing to, and therefore endorsing, external considerations of purpose, policy, and value. But Meyerson replies that such considerations may be viewed as part of, not separate from, the rules of the game.

  The primary purpose of the reference to a game in the last paragraph is to

  A. provide an example of how a principle has previously been applied
  B. demonstrate a point by means of an analogy
  C. emphasize the relative unimportance of an activity
  D. contrast two situations by exaggerating their differences
  E. dismiss an idea by portraying it as reprehensible
  B. demonstrate a point by means of an analogy

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  3rd paragraph ask us to "consider a game." That game has pretty clear rules but obviously has no moral authority. So it illustrates Meyerson's belief that formalism does not necessarily require objectivism. In other words, legal rules can be unambiguous (as the game is) without having ethical legitimacy (as the game doesn't). Option [demonstrate a point by...] points out that the game is intended to be analogous to the legal process, so it's correct here.

• Question 285:

  Two mannequins -- 1 and 2 -- will be dressed for display in outfits chosen from ten articles of clothing. Each article is in exactly one of three colors: navy, red, or yellow. There are three hats -- one in each color; three jackets -- one in each

  color; three skirts -- one in each color; and one red tie. Each mannequin wears exactly one of the hats, one of the jackets, and one of the skirts. Furthermore, their outfits must meet the following restrictions:

  Neither mannequin wears all three colors.

  Each mannequin wears a hat in a different color from the jacket it wears.

  Mannequin 2 wears the navy skirt.

  Mannequin 1 wears the tie.

  If mannequin 1 wears the navy jacket, which one of the following could be true?

  A. Mannequin 1 wears the yellow hat.
  B. Mannequin 1 wears the yellow skirt.
  C. Mannequin 2 wears the red hat.
  D. Mannequin 2 wears the yellow hat.
  E. Mannequin 2 wears the yellow jacket.
  E. Mannequin 2 wears the yellow jacket.

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  If mannequin 1 gets the navy jacket, then mannequin 1's colors are red and navy. So [Mannequin 1 wears the yellow hat.] and [Mannequin 1 wears the yellow skirt.], which give mannequin 1 yellow clothing, are impossible. One more

  deduction leads to the correct answer. Mannequin 2 gets either a navy hat or a navy jacket (Key Deductions).

  Here, mannequin 1 gets the navy jacket, and so mannequin 2 gets the navy hat. That kills [Mannequin 2 wears the red hat.]. and [Mannequin 2 wears the yellow hat.] So [Mannequin 2 wears the yellow jacket.] is correct.

• Question 286:

  Tom is test driving a blue car. After driving for a short while he comes to the following conclusion: Since this car is blue, it must not accelerate quickly. The foregoing conclusion can be properly drawn if it is also known that

  A. all red cars accelerate quickly
  B. there are some slow blue cars
  C. all blue cars may not accelerate slowly
  D. all cars that accelerate quickly are red
  E. all slow cars are red
  D. all cars that accelerate quickly are red

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  The given statement tells us only that the car is blue. For us to be assured that it is slow we must know either that every blue car is slow or that no blue car accelerates quickly. Option [all cars that accelerate quickly are red] restricts quick acceleration to red cars.

• Question 287:

  From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, three -- F, G, and H -- are rubies; three -- J, K, and M -- are sapphires; and four -- W, X, Y, and Z -- are topazes. The selection of stones must meet the

  following restrictions:

  At least two of the topazes are selected.

  If exactly two of the sapphires are selected, exactly one of the rubies is selected.

  If W is selected, neither H nor Z is selected.

  If M is selected, W is also selected.

  If Z is selected, which one of the following could be true?

  A. All three of the sapphires are selected.
  B. Both J and M are selected.
  C. Both K and M are selected.
  D. None of the rubies is selected.
  E. None of the sapphires is selected.
  E. None of the sapphires is selected.

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  Write out your roster, circle Z on it, and realize that that's a trigger for rejecting W (Rule 3's contrapositive) and thus for rejecting M (Rule 4's contrapositive). That's all we need. With sapphire M gone, clearly options [All three of the sapphires are selected.], [Both J and M are selected.], and [Both K and M are selected.] are impossible. And if option [None of the rubies is selected.] were true -- no rubies -- our remaining 2 sapphires and maximum of 3 topazes would leave us short of our desired total of 6. So [None of the sapphires is selected.] is possible by default. Indeed, all three rubies plus topazes X, Y, Z would constitute an acceptable set of 6.

• Question 288:

  Television executives recently announced that advertising time on television will cost 10 to 15 percent more next fall than it cost last fall. The executives argued that in spite of this increase, advertisers will continue to profit from television advertising, and so advertising time will be no harder to sell next fall than it was last fall.

  Which one of the following, if true, would most support the television executives' argument?

  A. Most costs of production and distribution of products typically advertised on television are expected to rise 3 to 7 percent in the next year.
  B. The system for rating the size of the audience watching any given television advertisement will change next fall.
  C. Next fall advertising time on television will no longer be available in blocks smaller than 30 seconds.
  D. The amount of television advertising time purchased by providers of services is increasing, while the amount of such time purchased by providers of products is decreasing.
  E. A recent survey has shown that the average number of hours people spend watching television is increasing at the rate of 2 percent every two months.
  E. A recent survey has shown that the average number of hours people spend watching television is increasing at the rate of 2 percent every two months.

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  TV and doctors, TV and doctors. . . Noticing a pattern in the subject matter in the beginning of this section? This time we get a strengthening question. We're told that advertising will be more expensive next year, but advertisers will still profit from those ads. The conclusion, set off in the final sentence by "and so," is that advertising time will be no harder to sell next fall than it was last fall. Perhaps this struck you as a bit shaky? The author doesn't say profits are rising, or even staying the same, but merely that profits will continue. If it's more expensive to advertise, might it not actually be harder to sell ads this fall? The author is assuming that despite increasing costs of TV advertising, something else will compensate for the increase and render the advertising just as valuable to advertisers despite the increase in cost. So we need to find some positive factor among the choices that would make us more likely to believe that ads will sell just as easily this fall, as the author contends. That may be as much of a prephrase as is possible here, so let's jump right to the choices.

• Question 289:

  In a school, 9 students, Andrew, Bach, Caesar, Drew, Elena, Fischer, Grant, Hughes, and Ileana are selected to form 3 debate teams – Team A, Team B and Team C - to participate in interschool competitions. The following information is known: Each team will have exactly 3 students and no student can be a part of more than one team Caesar cannot be selected in Team A if Ileana is not selected in Team A as well Andrew and Bach are in the same team and so are Elena and Grant Andrew and Caesar are not in the same team Bach and Ileana are not in the same team Drew and Elena are not in the same team

  In the previous question, in how many possible ways can the members of the other two teams be decided?

  A. One
  B. Two
  C. Three
  D. Four
  E. Six
  C. Three

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  Continuing with the below general explanation:

  Nothing can be said about the teams in which D, F and H are present.

  We can only conclude that since A and C are not in the same team, A must be in Team A along with B.

  Thus, the teams are:

  

  Thus, the possible scenarios are:

  

  Or

  

  Or

  

• Question 290:

  Jane works at a fashion design company, and is having problems getting dressed for work.

  She refuses to wear any color combination that does not go well together as many of her clients may look down upon this. She has two pairs of skirts, brown and blue; three blouses, white, sky blue, and gray; four pairs of stockings, red,

  black, brown, and blue; and two pairs of shoes, black and brown. The blue skirt cannot be worn with red or brown stockings. Gray does not go well with brown. Black does not go well with brown.

  If Jane wears a brown skirt and a white blouse, she could:

  A. not wear blue stockings.
  B. not wear brown shoes.
  C. not wear black shoes.
  D. wear blue stockings.
  E. wear red stockings.
  C. not wear black shoes.

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  Since black does not go well with brown, Jane would not be allowed to wear black shoes.