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Test of Essential Academic Skills - Math Problem Solving

Exam Details

  • Exam Code
    :TEAS-SECTION-3
  • Exam Name
    :Test of Essential Academic Skills - Math Problem Solving
  • Certification
    :Test of Essential Academic Skills
  • Vendor
    :TEAS
  • Total Questions
    :103 Q&As
  • Last Updated
    :May 10, 2024

TEAS Test of Essential Academic Skills TEAS-SECTION-3 Questions & Answers

  • Question 91:

    The following items were purchased at the grocery store.

    What was the average price paid for the items?

    A. $0.34

    B. $0.55

    C. $0.93

    D. $1.38

  • Question 92:

    What does 68% equal?

    A. 6800

    B. 0.68

    C. 0.0068

    D. 6.8

  • Question 93:

    Multiply 21/7 × 32/3.

    A. 11/3

    B. 132/45

    C. 76/7

    D. 4/7

  • Question 94:

    Find (27/9) × (√(25) × 2).

    A. 90

    B. 12

    C. 45

    D. 30

  • Question 95:

    What is the missing number in the sequence? 4, 6, 10, 18, ___, 66.

    A.45

    B. 34

    C. 54

    D. 22

  • Question 96:

    Enrique weighs 5 pounds more than twice Brendan's weight.

    If their total weight is 225 pounds, how much does Enrique weigh?

    A. 125 pounds

    B. 152 pounds

    C. 165 pounds

    D. 115 pounds

  • Question 97:

    What does (4x - y) + (-10 + y) equal if x = 3 and y = 4?

    A. 14

    B. 22

    C. -2

    D. 2

  • Question 98:

    A pasta salad was chilled in the refrigerator at 35°F overnight for 9 hours. The temperature of the pasta dish dropped from 86°F to 38°F.

    What was the average rate of cooling per hour?

    A. (0.532°)/hr

    B. (5.3°)/hr

    C. (4.8°)/hr

    D. (5.15°)/hr

  • Question 99:

    If Leonard bought 2 packs of batteries for x amount of dollars, how many packs of batteries could he purchase for $5.00 at the same rate?

    A. 10/x

    B. 2x

    C. 2/x

    D. 10x

  • Question 100:

    Choose the algebraic expression that best represents the following situation: Jeral's test score (J) was 5 points higher than half of Kara's test score (K).

    A. K = 1/2 × J - 5

    B. J = 1/2 × K + 5

    C. J = 2K - 5

    D. K = (J - 1/2) - 5

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