ASCP ASCP-MLT Online Practice Questions and Exam Preparation

ASCP ASCP-MLT Online Questions & Answers

• Question 511:

  Which of the following testing options would be classified as waived testing by CLIA standards?

  A. Complete blood count (CBC)
  B. PCR testing
  C. Blood glucose for home use
  D. Microscopic examination for the presence of bacteria
  C. Blood glucose for home use

• Question 512:

  Molarity x Molecular Weight x Volume = Grams Molecular Weight (aka Formula Weight) = 2(1) + 32 + 4(16) = 98 So, 4 x 98 x 0.2L = 78.4g What weight of H2SO4 is contained in 200 ml of a 4 molar H2SO4 solution? (Atomic weight: H= 1; S = 32; 0 = 16)

  A. 78.4 gm
  B. 156.8 gm
  C. 39.2 gm
  D. 15.68 gm
  E. 84 gm
  A. 78.4 gm

• Question 513:

  Chemistry

  Estrogen and progesterone markers are most commonly used to provide prognostic information about:

  A. Breast cancer
  B. Uterine cancer
  C. Menopause
  D. Cervical cancer
  A. Breast cancer

• Question 514:

  The correct answer for this question is 1300 mg/dL. The laboratorian performed a 1:4 dilution by adding 0.25 mL (or 250 microliters) of patient sample to 750 microliters of diluent. This creates a total volume of 1000 microliters. So, the patient sample is 250 microliters of the 1000 microliter mixed sample, or a ratio of 1:4. Therefore, the result given by the chemistry analyzer must be multiplied by a dilution factor of 4. 325 mg/dL x 4 = 1300 mg/dL.

  After experiencing extreme fatigue and polyuria, a patient's basic metabolic panel is analyzed in the laboratory. The result of the glucose is too high for the instrument to read. The laboratorian performs a dilution using 0.25 mL of patient sample to 750 microliters of diluent. The result now reads 325 mg/dL. How should the techologist report this patient's glucose result?

  A. 325 mg/dL
  B. 1300 mg/dL
  C. 975 mg/dL
  D. 1625 mg/dL
  B. 1300 mg/dL

• Question 515:

  Since hemoglobin is measured spectrophotometrically on hematology analzyers, interference from lipemia or icteric specimens can lead to decreased light detected and measured through the sample and therefore inaccurate hemoglobin results occur. On an electronic cell counter, hemoglobin determination may be falsely elevated caused by the presence of:

  A. Lipemic or icteric plasma
  B. Leukocytopenia or Leukocytosis
  C. Rouleaux or agglutinated RBCs
  D. Anemia or Polycythemia
  A. Lipemic or icteric plasma

• Question 516:

  Convert the following temperature from Fahrenheit to Celsius 102 degrees F

  A. 38.9 degrees C
  B. 14 degrees C
  C. 77 degrees C
  D. 39.2 degrees C
  A. 38.9 degrees C

• Question 517:

  Rapid vascular constriction, not dilation, immediately occurs when there is vascular injury in order to constrict the amount of blood that escapes the vessels; ultimately preventing massive loss of blood.

  Primary hemostatic processes resulting from vascular damage include all of the following EXCEPT:

  A. collagen activates glycoprotein IIb/IIIa during platelet activation
  B. von Willebrand factor mediates platelet adhesion
  C. platelet granule release and fibrinogen mediate platelet aggregation
  D. rapid and immediate vascular dilation occurs
  E. b and c
  D. rapid and immediate vascular dilation occurs

• Question 518:

  Escherichia coli and Klebsiella pneumoniae are two good quality control choices for the indole test. E. coli is indole positive, while K. pneumoniae is indole negative. A positive reaction is noted when there is a red layer at the top of the tube after the addition of Kov醕s reagent, while the negative result is a lack of color change in the top of the tube after the addition of Kov醕s reagent.

  Which one of the following combinations of organisms would be appropriate positive and negative controls to verify the specific test functions listed?

  A. Beta hemolysis - Escherichia coli and Streptococcus pyogenes
  B. Catalase - Staphylococcus aureus and Staphylococcus epidermidis
  C. Hydrogen sulfide production - proteus mirabilis and Salmonella typhi
  D. Indole - Escherichia coli and Klebsiella pneumonia
  E. Carbohydrate fermentation - Alcaligenes faecalis and Acinetobacter baumannii
  D. Indole - Escherichia coli and Klebsiella pneumonia

• Question 519:

  Gram positive organisms resist decolorization by ethyl alcohol. The large crystal violet- iodine complex is not able to penetrate the peptidoglycan layer, and is trapped within the cell in gram-positive organisms. Conversely, the outer membrane of gram-negative organisms is degraded and the thinner peptidoglycan layer of gram-negative cells is unable to retain the crystal violet-iodine complex and the color is lost.

  What is the purpose of using ethyl alcohol or acetone in the gram stain procedure:

  A. Fix all gram positive organisms
  B. Decolorize all gram positive organisms
  C. Decolorize all gram negative organisms
  D. Fix all gram negative organisms
  C. Decolorize all gram negative organisms

• Question 520:

  To prevent blood from clotting the specimen must be:

  A. collected in a tube containing an anticoagulant.
  B. inverted right after collection.
  C. centrifuged right after collection.
  D. both A and B
  D. both A and B