Cisco 200-120 Online Practice Questions and Exam Preparation

Cisco 200-120 Online Questions & Answers

• Question 321:

  Which router IOS commands can be used to troubleshoot LAN connectivity problems? (Choose three.)

  A. ping
  B. tracert
  C. ipconfig
  D. show ip route
  E. winipcfg
  F. show interfaces
  A. ping
  D. show ip route
  F. show interfaces

  ---

  Ping, show ip route, and show interfaces are all valid troubleshooting IOS commands. Tracert, ipconfig, and winipcfg are PC commands, not IOS.

• Question 322:

  Which standards-based First Hop Redundancy Protocol is a Cisco supported alternative to Hot Standby Router Protocol?

  A. VRRP
  B. GLBP
  C. TFTP
  D. DHCP
  A. VRRP

• Question 323:

  Which two of these statements are true of IPv6 address representation? (Choose two.)

  A. There are four types of IPv6 addresses: unicast, multicast, anycast, and broadcast.
  B. A single interface may be assigned multiple IPv6 addresses of any type.
  C. Every IPv6 interface contains at least one loopback address.
  D. The first 64 bits represent the dynamically created interface ID.
  E. Leading zeros in an IPv6 16 bit hexadecimal field are mandatory.
  B. A single interface may be assigned multiple IPv6 addresses of any type.
  C. Every IPv6 interface contains at least one loopback address.

  ---

  A single interface may be assigned multiple addresses of any type (unicast, anycast, multicast).

  

  Every IPv6-enabled interface must contain at least one loopback and one link-local address.

  

  Optionally, every interface can have multiple unique local and global addresses.

  

  Reference: IPv6 Addressing at a Glance ?Cisco PDF

• Question 324:

  Refer to the exhibit.

  

  Which address and mask combination represents a summary of the routes learned by EIGRP?

  A. 192.168.25.0 255.255.255.240
  B. 192.168.25.0 255.255.255.252
  C. 192.168.25.16 255.255.255.240
  D. 192.168.25.16 255.255.255.252
  E. 192.168.25.28 255.255.255.240
  F. 192.168.25.28 255.255.255.252
  C. 192.168.25.16 255.255.255.240

  ---

  The binary version of 20 is 10100.

  The binary version of 16 is 10000.

  The binary version of 24 is 11000.

  The binary version of 28 is 11100.

  The subnet mask is /28. The mask is 255.255.255.240.

  Note:

  From the output above, EIGRP learned 4 routes and we need to find out the summary of them:

  +

  192.168.25.16

  +

  192.168.25.20

  +

  192.168.25.24

  +

  192.168.25.28

  -> The increment should bE. 28 ?16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240.

  So, the best answer should be 192.168.25.16 255.255.255.240.

• Question 325:

  RouterA is unable to reach RouterB. Both routers are running IOS version 12.0.

  

  After reviewing the command output and graphic, what is the most likely cause of the problem?

  A. incorrect bandwidth configuration
  B. incorrect LMI configuration
  C. incorrect map statement
  D. incorrect IP address
  C. incorrect map statement

  ---

  First we have to say this is an unclear question and it is wrong. The "frame-relay map ip" statement is correct thus none of the four answers above is correct. But we guess there is a typo in the output. Maybe the "ip address 172.16.100.2

  255.255.0.0 command should be "ip address 172.16.100.1 255.255.0.0. That makes answer C correct.

• Question 326:

  Refer to the exhibit.

  

  A network administrator configures a new router and enters the copy startup-config running-config command on the router. The network administrator powers down the router and sets it up at a remote location. When the router starts, it enters the system configuration dialog as shown. What is the cause of the problem?

  A. The network administrator failed to save the configuration.
  B. The configuration register is set to 0x2100.
  C. The boot system flash command is missing from the configuration.
  D. The configuration register is set to 0x2102.
  E. The router is configured with the boot system startup command.
  A. The network administrator failed to save the configuration.

  ---

  The "System Configuration Dialog" appears only when no startup configuration file is found. The network administrator has made a mistake because the command "copy startup-config running-config" will copy the startup config (which is

  empty) over the running config (which is configured by the administrator). So everything configured was deleted.

  Note: We can tell the router to ignore the start-up configuration on the next reload by setting the register to 0?142. This will make the "System Configuration Dialog" appear at the next reload.

• Question 327:

  Refer to the exhibit.

  

  What is the meaning of the output MTU 1500 bytes?

  A. The maximum number of bytes that can traverse this interface per second is 1500.
  B. The minimum segment size that can traverse this interface is 1500 bytes.
  C. The maximum segment size that can traverse this interface is 1500 bytes.
  D. The minimum packet size that can traverse this interface is 1500 bytes.
  E. The maximum packet size that can traverse this interface is 1500 bytes.
  F. The maximum frame size that can traverse this interface is 1500 bytes.
  E. The maximum packet size that can traverse this interface is 1500 bytes.

  ---

  The Maximum Transmission Unit (MTU) defines the maximum Layer 3 packet (in bytes) that can be transmitted out the interface.

• Question 328:

  What are two benefits of using NAT? (Choose two.)

  A. NAT facilitates end-to-end communication when IPsec is enabled.
  B. NAT eliminates the need to re-address all hosts that require external access.
  C. NAT conserves addresses through host MAC-level multiplexing.
  D. Dynamic NAT facilitates connections from the outside of the network.
  E. NAT accelerates the routing process because no modifications are made on the packets.
  F. NAT protects network security because private networks are not advertised.
  B. NAT eliminates the need to re-address all hosts that require external access.
  F. NAT protects network security because private networks are not advertised.

  ---

  By not revealing the internal IP addresses, NAT adds some security to the inside network -> F is correct.

  NAT has to modify the source IP addresses in the packets -> E is not correct.

  Connection from the outside of the network through a "NAT" network is more difficult than a more network because IP addresses of inside hosts are hidden -> C is not correct.

  In order for IPsec to work with NAT we need to allow additional protocols, including Internet Key Exchange (IKE), Encapsulating Security Payload (ESP) and Authentication Header (AH) -> more complex -> A is not correct.

  By allocating specific public IP addresses to inside hosts, NAT eliminates the need to re-address the inside hosts -> B is correct.

  NAT does conserve addresses but not through host MAC-level multiplexing. It conserves addresses by allowing many private IP addresses to use the same public IP address to go to the Internet -> C is not correct.

• Question 329:

  Which IPv6 header field is equivalent to the TTL?

  A. Hop Limit
  B. Flow Label
  C. TTD
  D. Hop Count
  E. Scan Timer
  A. Hop Limit

• Question 330:

  A switch is configured with all ports assigned to VLAN 2 with full duplex FastEthernet to segment existing departmental traffic. What is the effect of adding switch ports to a new VLAN on the switch?

  A. More collision domains will be created.
  B. IP address utilization will be more efficient.
  C. More bandwidth will be required than was needed previously.
  D. An additional broadcast domain will be created.
  D. An additional broadcast domain will be created.

  ---

  Each VLAN creates its own broadcast domain. Since this is a full duplex switch, each port is a separate collision domain.