Cisco 200-120 Online Practice Questions and Exam Preparation

Cisco 200-120 Online Questions & Answers

• Question 221:

  An administrator is trying to ping and telnet from SwitchC to RouterC with the results shown below.

  

  Click the console connected to RouterC and issue the appropriate commands to answer the questions.

  

  

  Which will fix the issue and allow ONLY ping to work while keeping telnet disabled?

  A. Correctly assign an IP address to interface fa0/1.
  B. Change the ip access-group command on fa0/0 from "in" to "out".
  C. Remove access-group 106 in from interface fa0/0 and add access-group 115 in.
  D. Remove access-group 102 out from interface s0/0/0 and add access-group 114 in.
  E. Remove access-group 106 in from interface fa0/0 and add access-group 104 in.
  E. Remove access-group 106 in from interface fa0/0 and add access-group 104 in.

  ---

  Let's have a look at the access list 104:

  

  The question does not ask about ftp traffic so we don't care about the two first lines. The 3rd line denies all telnet traffic and the 4th line allows icmp traffic to be sent (ping). Remember that the access list 104 is applied on the inbound direction so the 5th line "access-list 104 deny icmp any any echo-reply" will not affect our icmp traffic because the "echo-reply" message will be sent over the outbound direction.

• Question 222:

  Refer to the exhibit.

  

  The company uses EIGRP as the routing protocol. What path will packets take from a host on the 192.168.10.192/26 network to a host on the LAN attached to router R1?

  A. The path of the packets will be R3 to R2 to R1.
  B. The path of the packets will be R3 to R1 to R2.
  C. The path of the packets will be both R3 to R2 to R1 AND R3 to R1.
  D. The path of the packets will be R3 to R1.
  D. The path of the packets will be R3 to R1.

  ---

  Host on the LAN attached to router R1 belongs to 192.168.10.64/26 subnet. From the output of the routing table of R3 we learn this network can be reach via 192.168.10.9, which is an IP address in 192.168.10.8/30 network (the network between R1 and R3) -> packets destined for 192.168.10.64 will be routed from R3 -> R1 -> LAN on R1.

• Question 223:

  Refer to the exhibit.

  

  At the end of an RSTP election process, which access layer switch port will assume the discarding role?

  A. Switch3, port fa0/1
  B. Switch3, port fa0/12
  C. Switch4, port fa0/11
  D. Switch4, port fa0/2
  E. Switch3, port Gi0/1
  F. Switch3, port Gi0/2
  C. Switch4, port fa0/11

  ---

  In this question, we only care about the Access Layer switches (Switch3 and 4). Switch 3 has a lower bridge ID than Switch 4 (because the MAC of Switch3 is smaller than that of Switch4) so both ports of Switch3 will be in forwarding state. The

  alternative port will surely belong to Switch4.

  Switch4 will need to block one of its ports to avoid a bridging loop between the two switches. But how does Switch4 select its blocked port? Well, the answer is based on the BPDUs it receives from Switch3. A BPDU is superior to another if it

  has:

  1.

  A lower Root Bridge ID

  2.

  A lower path cost to the Root

  3.

  A lower Sending Bridge ID

  4.

  A lower Sending Port ID

  These four parameters are examined in order. In this specific case, all the BPDUs sent by Switch3 have the same Root Bridge ID, the same path cost to the Root and the same Sending Bridge ID. The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). In this case the port priorities are equal because they use the default value, so Switch4 will compare port index values, which are unique to each port on the switch, and because Fa0/12 is inferior to Fa0/1, Switch4 will select the port connected with Fa0/1 (of Switch3) as its root port and block the other port -> Port fa0/11 of Switch4 will be blocked (discarding role).

• Question 224:

  Refer to the exhibit.

  

  A new subnet with 60 hosts has been added to the network. Which subnet address should this network use to provide enough usable addresses while wasting the fewest addresses?

  A. 192.168.1.56/26
  B. 192.168.1.56/27
  C. 192.168.1.64/26
  D. 192.168.1.64/27
  C. 192.168.1.64/26

  ---

  A subnet with 60 host is 2*2*2*2*2*2 = 64 -2 == 62 6 bits needed for hosts part. Therefore subnet bits are 2 bits (8-6) in fourth octet. 8bits+ 8bits+ 8bits + 2bits = /26 /26 bits subnet is 24bits + 11000000 = 24bits + 192 256 ?192 = 64 0 -63 64 ?127

• Question 225:

  Which option is a valid IPv6 address?

  A. 2001:0000:130F::099a::12a
  B. 2002:7654:A1AD:61:81AF:CCC1
  C. FEC0:ABCD:WXYZ:0067::2A4
  D. 2004:1:25A4:886F::1
  D. 2004:1:25A4:886F::1

  ---

  An IPv6 address is represented as eight groups of four hexadecimal digits, each group representing 16 bits (two octets). The groups are separated by colons (:). An example of an IPv6 address is 2001:0db8:85a3:0000:0000:8a2e:0370:7334. The leading 0's in a group can be collapsed using ::, but this can only be done once in an IP address.

• Question 226:

  Which statement describes the process of dynamically assigning IP addresses by the DHCP server?

  A. Addresses are allocated after a negotiation between the server and the host to determine the length of the agreement.
  B. Addresses are permanently assigned so that the hosts uses the same address at all times.
  C. Addresses are assigned for a fixed period of time, at the end of the period, a new request for an address must be made.
  D. Addresses are leased to hosts, which periodically contact the DHCP server to renew the lease.
  D. Addresses are leased to hosts, which periodically contact the DHCP server to renew the lease.

  ---

  The DHCP lifecycle consists of the following:

  Allocation: A client begins with no active lease, and hence, no DHCP-assigned address. It acquires a lease through a process of allocation.

  

  Reallocation: If a client already has an address from an existing lease, then when it reboots or starts up after being shut down, it will contact the DHCP server that granted it the lease to confirm the lease and acquire operating parameters.

  

  This is sometimes called reallocation; it is similar to the full allocation process but shorter.

  Normal Operation: Once a lease is active, the client functions normally, using its assigned IP address and other parameters during the "main part" of the lease. The client is said to be bound to the lease and the address.

  

  Renewal: After a certain portion of the lease time has expired, the client will attempt to contact the server that initially granted the lease, to renew the lease so it can keep using its IP address.

  

  Rebinding. If renewal with the original leasing server fails (because, for example, the server has been taken offline), then the client will try to rebind to any active DHCP server, trying to extend its current lease with any server that will allow

  

  it to do so.

  Release: The client may decide at any time that it no longer wishes to use the IP address it was assigned, and may terminate the lease, releasing the IP address.

  

• Question 227:

  What is the first 24 bits in a MAC address called?

  A. NIC
  B. BIA
  C. OUI
  D. VAI
  C. OUI

  ---

  An Organizationally Unique Identifier (OUI) is a 24-bit number that uniquely identifies a vendor, manufacturer, or other organization globally or worldwide. They are used as the first 24 nits of the MAC address to uniquely identify a particular piece of equipment.

• Question 228:

  Refer to the exhibit.

  

  Why is flash memory erased prior to upgrading the IOS image from the TFTP server?

  A. The router cannot verify that the Cisco IOS image currently in flash is valid.
  B. Flash memory on Cisco routers can contain only a single IOS image.
  C. Erasing current flash content is requested during the copy dialog.
  D. In order for the router to use the new image as the default, it must be the only IOS image in flash.
  C. Erasing current flash content is requested during the copy dialog.

  ---

  During the copy process, the router asked "Erasing flash before copying? [confirm]" and the administrator confirmed (by pressing Enter) so the flash was deleted. Note: In this case, the flash has enough space to copy a new IOS without deleting the current one. The current IOS is deleted just because the administrator wants to do so. If the flash does not have enough space you will see an error message like this:

  

• Question 229:

  A network administrator needs to allow only one Telnet connection to a router. For anyone viewing the configuration and issuing the show run command, the password for Telnet access should be encrypted. Which set of commands will accomplish this task?

  A. service password-encryption access-list 1 permit 192.168.1.0 0.0.0.255 line vty 0 4 login password cisco access-class 1
  B. enable password secret line vty 0 login password cisco
  C. service password-encryption line vty 1 login password cisco
  D. service password-encryption line vty 0 4 login password cisco
  C. service password-encryption line vty 1 login password cisco

  ---

  Only one VTY connection is allowed which is exactly what's requested.

  Incorrect answer: command.

  line vty0 4

  would enable all 5 vty connections.

• Question 230:

  Which two statements about static NAT translations are true? (Choose two.)

  A. They allow connections to be initiated from the outside.
  B. They require no inside or outside interface markings because addresses are statically defined.
  C. They are always present in the NAT table.
  D. They can be configured with access lists, to allow two or more connections to be initiated from the outside.
  A. They allow connections to be initiated from the outside.
  C. They are always present in the NAT table.

  ---

  Static NAT is to map a single outside IP address to a single inside IP address. This is typically done to allow incoming connections from the outside (Internet) to the inside. Since these are static, they are always present in the NAT table even if they are not actively in use.