Oracle 1Z0-803 Online Practice Questions and Exam Preparation

Oracle 1Z0-803 Online Questions & Answers

• Question 161:

  Class StaticField {

  static int i = 7;

  public static void main(String[] args) {

  StaticFied obj = new StaticField();

  obj.i++;

  StaticField.i++;

  obj.i++;

  System.out.println(StaticField.i + " "+ obj.i);

  }

  }

  What is the result?

  A. 10 10
  B. 8 9
  C. 9 8
  D. 7 10
  A. 10 10

• Question 162:

  Given:

  public class Marklist {

  int num;

  public static void graceMarks(Marklist obj4) {

  obj4.num += 10;

  }

  public static void main(String[] args) {

  MarkList obj1 = new MarkList();

  MarkList obj2 = obj1;

  MarkList obj1 = null;

  obj2.num = 60;

  graceMarks(obj2);

  }

  }

  How many objects are created in the memory runtime?

  A. 1
  B. 2
  C. 3
  D. 4
  B. 2

  ---

  obj1 and obj3.

  when you do e2 = e1 you're copying object references - you're not making a copy of the object - and so the variables e1 and e2 will both point to the same object.

• Question 163:

  Given:

  

  What is the result?

  A. Red 0 Orange 0 Green 3
  B. Red 0 Orange 0 Green 6
  C. Red 0 Orange 1
  D. Green 4
  E. Compilation fails
  E. Compilation fails

• Question 164:

  Given:

  public class ScopeTest {

  int j, int k;

  public static void main(String[] args) {

  ew ScopeTest().doStuff(); }

  void doStuff() {

  nt x = 5;

  oStuff2();

  System.out.println("x");

  }

  void doStuff2() {

  nt y = 7;

  ystem.out.println("y");

  or (int z = 0; z < 5; z++) {

  ystem.out.println("z");

  ystem.out.println("y");

  }

  Which two items are fields?

  A. j
  B. k
  C. x
  D. y
  E. z
  A. j
  B. k

• Question 165:

  Given:

  

  A. a, e i, o
  B. a, e o, o
  C. e, e I, o
  D. e, e o, o
  D. e, e o, o

• Question 166:

  The protected modifier on a Field declaration within a public class means that the field ______________.

  A. Cannot be modified
  B. Can be read but not written from outside the class
  C. Can be read and written from this class and its subclasses only within the same package
  D. Can be read and written from this class and its subclasses defined in any package
  D. Can be read and written from this class and its subclasses defined in any package

  ---

  Reference: http://beginnersbook.com/2013/05/java-access-modifiers/

• Question 167:

  View the exhibit:

  public class Student {

  public String name = "";

  public int age = 0;

  public String major = "Undeclared";

  public boolean fulltime = true;

  public void display() {

  System.out.println("Name: " + name + " Major: " + major); } public boolean isFullTime() { return fulltime;

  }

  }

  Which line of code initializes a student instance?

  A. Student student1;
  B. Student student1 = Student.new();
  C. Student student1 = new Student();
  D. Student student1 = Student();
  C. Student student1 = new Student();

• Question 168:

  Given:

  public class ColorTest {

  public static void main(String[] args) {

  String[] colors = {"red", "blue","green","yellow","maroon","cyan"}; int count = 0;

  for (String c : colors) {

  if (count >= 4) {

  break;

  }

  else {

  continue;

  }

  if (c.length() >= 4) {

  colors[count] = c.substring(0,3);

  }

  count++;

  }

  System.out.println(colors[count]);

  }

  }

  What is the result?

  A. Yellow
  B. Maroon
  C. Compilation fails
  D. A StringIndexOutOfBoundsException is thrown at runtime.
  C. Compilation fails

  ---

  The line, if (c.length() >= 4) {, is never reached. This causes a compilation error.

  Note: The continue statement skips the current iteration of a for, while , or do-while loop. An unlabeled break statement terminates the innermost switch, for, while, or do-while statement, but a labeled break terminates an outer statement.

• Question 169:

  Given the code fragments:

  

  What is the result?

  A. Super Sub Sub
  B. Contract Contract Super
  C. Compilation fails at line n1
  D. Compilation fails at line n2
  D. Compilation fails at line n2

• Question 170:

  Given the code fragment:

  System.out.printIn("Result: " + 2 + 3 + 5); System.out.printIn("Result: " + 2 + 3 * 5);

  What is the result?

  A. Result: 10 Result: 30
  B. Result: 10 Result: 25
  C. Result: 235 Result: 215
  D. Result: 215 Result: 215
  E. Compilation fails
  C. Result: 235 Result: 215

  ---

  First line:

  System.out.println("Result: " + 2 + 3 + 5);

  String concatenation is produced.

  Second line:

  System.out.println("Result: " + 2 + 3 * 5);

  3*5 is calculated to 15 and is appended to string 2. Result 215.

  The output is:

  Result: 235

  Result: 215

  Note #1:

  To produce an arithmetic result, the following code would have to be used:

  System.out.println("Result: " + (2 + 3 + 5));

  System.out.println("Result: " + (2 + 1 * 5));

  run:

  Result: 10

  Result: 7

  Note #2:

  If the code was as follows:

  System.out.println("Result: " + 2 + 3 + 5");

  System.out.println("Result: " + 2 + 1 * 5");

  The compilation would fail. There is an unclosed string literal, 5", on each line.