1Z0-061 Exam Details

  • Exam Code
    :1Z0-061
  • Exam Name
    :Oracle Database 12c: SQL Fundamentals
  • Certification
    :Oracle Certifications
  • Vendor
    :Oracle
  • Total Questions
    :339 Q&As
  • Last Updated
    :Oct 10, 2022

Oracle 1Z0-061 Online Questions & Answers

  • Question 61:

    View the Exhibit and examine the structure of CUSTOMERS table.

    Evaluate the following query:

    Which statement is true regarding the above query?

    A. It executes successfully.
    B. It produces an error because the condition on the CUST_CITY column is not valid.
    C. It produces an error because the condition on the CUST_FIRST_NAME column is not valid.
    D. It produces an error because conditions on the CUST_CREDIT_LIMIT column are not valid.

  • Question 62:

    Examine these statements:

    CREATE ROLE registrar;

    GRANT UPDATE ON student_grades TO registrar;

    GRANT registrar to user1, user2, user3;

    What does this set of SQL statements do?

    A. The set of statements contains an error and does not work.
    B. It creates a role called REGISTRAR, adds the MODIFY privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
    C. It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
    D. It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and creates three users with the role.
    E. It creates a role called REGISTRAR, adds the UPDATE privilege on three users, and gives the REGISTRAR role to the STUDENT_GRADES object.
    F. It creates a role called STUDENT_GRADES, adds the UPDATE privilege on three users, and gives the UPDATE role to the registrar.

  • Question 63:

    View the Exhibit and examine the description for the CUSTOMERS table.

    You want to update the CUST_INCOME_LEVEL and CUST_CREDIT_LIMIT columns for the customer with the CUST_ID 2360. You want the value for the CUST_INCOME_LEVEL to have the same value as that of the customer with the CUST_ID 2560 and the CUST_CREDIT_LIMIT to have the same value as that of the customer with CUST_ID 2566.

    Which UPDATE statement will accomplish the task?

    A. UPDATE customersSET cust_income_level = (SELECT cust_income_levelFROM customersWHERE cust_id = 2560),cust_credit_limit = (SELECT cust_credit_limitFROM customersWHERE cust_id = 2566)WHERE cust_id=2360;
    B. UPDATE customersSET (cust_income_level, cust_credit_limit) = (SELECTcust_income_level, cust_credit_limitFROM customersWHERE cust_id=2560 OR cust_id=2566)WHERE cust_id=2360;
    C. UPDATE customersSET (cust_income_level, cust_credit_limit) = (SELECTcust_income_level, cust_credit_limitFROM customersWHERE cust_id IN(2560, 2566)WHERE cust_id=2360;
    D. UPDATE customersSET (cust_income_level, cust_credit_limit) = (SELECTcust_income_level, cust_credit_limitFROM customersWHERE cust_id=2560 AND cust_id=2566)WHERE cust_id=2360;

  • Question 64:

    See the Exhibit and examine the structure and data in the INVOICE table: Exhibit:

    Which two SQL statements would execute successfully? (Choose two.)

    A. SELECT MAX(inv_date), MIN(cust_id) FROM invoice;
    B. SELECT MAX(AVG(SYSDATE - inv_date)) FROM invoice;
    C. SELECT (AVG(inv_date) FROM invoice;
    D. SELECT AVG(inv_date - SYSDATE), AVG(inv_amt) FROM invoice;

  • Question 65:

    Which SQL statement displays the date March 19, 2001 in a format that appears as "Nineteenth of March 2001 12:00:00 AM"?

    A. SELECTTO_CHAR(TO_DATE('19-Mar-2001', `DD-Mon-YYYY'), `fmDdspth"of" Month YYYY fmHH:MI:SS AM') NEW_DATE. FROM dual;
    B. SELECTTO_CHAR(TO_DATE('19-Mar-2001', `DD-Mon-YYYY'), `Ddspth"of" Month YYYY fmHH:MI:SS AM') NEW_DATEFROM dual;
    C. SELECTTO_CHAR(TO_DATE('19-Mar-2001', `DD-Mon-YYYY'), `fmDdspth "of" Month YYYYHH:MI:SS AM') NEW_DATE FROM dual;
    D. SELECTTO_CHAR(TO_DATE('19-Mar-2001', `DD-Mon-YYYY), `fmDdspth "of" Month YYYYfmtHH:HI:SS AM') NEW_DATE FROM dual;

  • Question 66:

    You issued the following command:

    SQL> DROP TABLE employees;

    Which three statements are true?

    A. All uncommitted transactions are committed.
    B. All indexes and constraints defined on the table being dropped are also dropped.
    C. Sequences used in the employees table become invalid.
    D. The space used by the employees table is reclaimed immediately.
    E. The employees table can be recovered using the rollback command.
    F. The employees table is moved to the recycle bin.

  • Question 67:

    You want to display 5 percent of the employees with the highest salaries in the EMPLOYEES table. Which query will generate the required result?

    A. Option A
    B. Option B
    C. Option C
    D. Option D

  • Question 68:

    Which three SQL statements would display the value 1890.55 as $1, 890.55? (Choose three.)

    A. SELECT TO_CHAR(1890.55, '$0G000D00')FROM DUAL;
    B. SELECT TO_CHAR(1890.55, '$9, 999V99')FROM DUAL;
    C. SELECT TO_CHAR(1890.55, '$99, 999D99')FROM DUAL;
    D. SELECT TO_CHAR(1890.55, '$99G999D00')FROM DUAL;
    E. SELECT TO_CHAR(1890.55, '$99G999D99')FROM DUAL;

  • Question 69:

    Examine the structure of the PROMOTIONS table:

    The management wants to see a report of unique promotion costs in each promotion category. Which query would achieve the required result?

    A. SELECT DISTINCT promo_cost, promo_category FROM promotions;
    B. SELECT promo_category, DISTINCT promo_cost FROM promotions;
    C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
    D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;

  • Question 70:

    Which normal form is a table in if it has no multi-valued attributes and no partial dependencies?

    A. First normal form
    B. Second normal form
    C. Third normal form
    D. Fourth normal form

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