What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
template
ostream and out;
Out(ostream and o): out(o){}
void operator()(const T and val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++ ; } }; int main() { vector generate(v1.begin(), v1.end(), Sequence(1)); set deque reverse(v1.begin(),v1.end()); reverse(s1.begin(), s1.end()); reverse(d1.begin(), d1.end()); for_each(v1.begin(), v1.end(), Out for_each(s1.begin(), s1.end(), Out for_each(d1.begin(), d1.end(), Out return 0; } Program outputs:
B. 1 2 3 4 5 1 2 3 4 5 5 4 3 2 1
C. no output
D. 1 2 3 4 5 5 4 3 2 1 1 2 3 4 5
E. compilation error
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main ()
{
int t[] = {1, 2 ,3 ,4 ,5, 6 , 7, 8 , 9, 10};
vector
deque
vector
deque
d1.erase(it2+5);
it2 = d1.begin();
cout<<*(it2+5)<<" ";
v1.erase(it1+5);
it1 = v1.begin();
cout<<*(it1+5)< }
B. program outputs: 6 6
C. compilation error
D. result is unpredictable
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B {
int val;
public:
B(int v):val(v){}
operator int() { return val;}
};
template
ostream and out;
Out(ostream and o): out(o){}
void operator() (const T and val ) { out< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; bool predicate(int v) { return v%2==0; } int main() { vector generate_n(v1.begin(), 10, Sequence(1)); for_each(v1.begin(), remove_if(v1.begin(), v1.end(), predicate), Out return 0;} Program outputs:
B. 1 3 5 7 9
C. 2 4 6 8 10
D. compilation error
E. no output
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
void print(int v) { cout< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return 10*(1+(start++ %3)); } }; int main() { vector generate_n(v1.begin(), 10, Sequence(1)); remove(v1.begin(), v1.end(), 10); for_each(v1.begin(), v1.end(), print);cout< return 0; } Program outputs:
B. 20 30 20 30 20 30 20
C. 20 30 20 30 20 30 20 30 10 20
D. compilation error
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main () {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
vector
vector
cout<< it?v.begin()< return 0; } Program outputs:
B. 3
C. 1
D. 15
E. compilation error
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1.1 2.2 3.3
#include
#include
using namespace std;
int main ()
{
int a,b,c;
cin>>a>>b>>c;
cout< return 0; } Program will output:
B. 1 2 3
C. 1.12.23.3
D. 1.1 2.2 3.3
E. none of these
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
while (start != end) {
std::cout << *start << " "; start++;
}
}
class A {
int a;
public:
A(int a):a(a){}
operator int () const { return a;}int getA() const { return a;}
};
struct R {
int val;
R(int v):val(v){}
bool operator ()(const A and a) { return a>val;} };
int main() {
int t1[] ={ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
list l1(t1, t1 + 10);
R r(4);l1.remove_if(r);
print(l1.begin(), l1.end()); cout< return 0; }
B. program outputs: 5 6 7 8 9 10
C. program outputs: 1 2 3 4 5
D. program outputs: 6 7 8 9 10
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main(){
vector
set
for(int i=10; i>0; i??) {
v.push_back(i);
s.push_back(i);
}
print(v.begin(), v.end()); print(s.begin(), s.end());cout< return 0; }
B. 10 9 8 7 6 5 4 3 2 1 10 9 8 7 6 5 4 3 2 1
C. 10 9 8 7 6 5 4 3 2 1 and unpredictable sequence of number range 1 to 10
D. compilation error
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1 2 3 4 quit
#include
#include
#include
#include
using namespace std;
template
ostream and out;
Out(ostream and o): out(o){}
void operator() (const T and val ) {out< int main () { list while(cin.good()) { string s; cin>>s; if (s == "quit") break; l.push_back(s); } for_each(l.begin(), l.end(), Out return 0; } Program will output:
B. 1 2 3 4 quit
C. 1 D. program runs forever without output
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B and v) const { return val ostream and operator <<(ostream and out, const B and v) { out< template ostream and out; Out(ostream and o): out(o){} void operator() (const T and val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={5,6,8,2,1}; vector v1(10,0); sort(t1, t1+5); sort(t2, t2+5); set_symmetric_difference(t2,t2+5,t1,t1+5,v1.begin()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs:
B. 3 4 0 0 0 0 0 0 0 0
C. 6 8 0 0 0 0 0 0 0 0
D. compilation error
E. 3 4 6 8 0 0 0 0 0 0
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