What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
map
for(int i=0; i < 10; i++) {
m[i]=t[i];
}
pair
map
if (it != m.end())
{
cout< } else { cout<<"Not found!\n"; } return 0; } Program outputs:
B. Not found!
C. 10
D. compilation error
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B and v) const { return val ostream and operator <<(ostream and out, const B and v) { out< template ostream and out; Out(ostream and o): out(o){} void operator() (const T and val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; set s1(t, t+10); sort(s1.begin(), s1.end()); for_each(s1.begin(), s1.end(), Out(cout));cout< return 0; } Program outputs:
B. 1 2 3 4 5 6 7 8 9 10
C. compilation error
D. 10 9 8 7 6 5 4 3 2 1
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A
{
int a;
public:
A(int a) {this?>a = a; c++;}
~A() { c??;}
static int c;
};
int A::c(0);
int main ()
{
A t[] = {0, 1, 2, 3, 4, 5, 6, 7, 8 , 9};
vectorv1(t, t+10);
dequed1(v1.begin(), v1.end());
deque d2;
d2 = d1;
cout< return 0; } How many objects of type A will be created:
B. 20
C. 30
D. 40
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
list
multiset
if (s1.count(3) == 2) {
s1.erase(3);
}
for(multiset
cout<<*i<<" ";
}
return 0;
}
A. program outputs: 1 2 3 4 5What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
class A
{
int a;
public:
A():a(0){} A(int a){ this?>a = a;}
void setA(int a) {this?>a = a;}
int getA() {return a;}
};
ostream andoperator<<(ostream and cout, A and a)
{
cout<< a.getA();
return cout;
}
int main ()
{
vector
v.push_back(new A(1));
vector
for(it = v.begin(); it != v.end(); it++)
{
cout<<*it<<" ";
}
cout< return 0; }
B. program outputs 0 0 0 0 0 0
C. compilation error
D. program outputs 1 1 1 1 1 1
E. none of these
What happens when you attempt to compile and run the following code?
#include
#include
int main ()
{
int t[]={1,2,3,4,5};
std::vector
std::vector
v1.resize(10);
v2.reserve(10);
std::vector
while (i != v1.end()) { std::cout< i = v2.begin();ii=0; while (i != v2.end()) { std::cout< return 0; }
B. compilation error
C. program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
D. program outputs 1 2 3 4 5 0 0 0 0 0 1 2 3 4 5 0 0 0 0 0
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B and v) const { return val ostream and operator <<(ostream and out, const B and v) { out< template ostream and out; Out(ostream and o): out(o){} void operator() (const T and val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector v1(10,0); sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); inplace_merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs:
B. 3 2 4 1 5 6 7 8 9 10
C. 3 2 4 1 5 6 10 8 7 9
D. 1 2 3 4 5 6 7 8 9 10
E. compilation error
What happens when you attempt to compile and run the following code? Choose all that apply.
#include
#include
using namespace std;
int main ()
{
vector
v1.push_back(3);
cout< return 0; }
B. program displays 10 3
C. size of vector v1 is 11
D. all elements of vector v1 are of the same value
Which changes introduced independently will allow code to compile and display 0 1 8 9 (choose all that apply)
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
A t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vectorv(t, t+10);
s1.insert(v.begin(),v.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(set::iterator i=s1.begin();i!= s1.end(); i++) {
cout<
}
cout< return 0; }
B. bool operator < (const A and b) const { return a
C. bool operator < (const A and b) const { return b.a
D. bool operator < (const A and a, const A and b) { return a.getA()
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int () const { return val;} };
ostream and operator <<(ostream and out, const B and v) { out<
ostream and out;
Out(ostream and o): out(o){}
void operator() (const T and val ) { out< struct Add { B operator()(B and a, B and b) { return a+b; } }; int main() { B t[]={1,2,3,4,5,6,7,8,9,10}; vector v1(t, t+10); vector v2(10); transform(v1.begin(), v1.end(), v2.begin(), bind2nd(Add(),1)); for_each(v2.rbegin(), v2.rend(), Out(cout));cout< return 0; } Program outputs:
B. 2 3 4 5 6 7 8 9 10 11
C. 10 9 8 7 6 5 4 3 2 1
D. 11 10 9 8 7 6 5 4 3 2
E. compilation error
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