IBM C2090-545 Online Practice Questions and Exam Preparation

IBM C2090-545 Online Questions & Answers

• Question 1:

  Which of the following statement isTRUE about a REPEAT loop?

  A. The condition is checked at the end of the loop.
  B. The condition is checked at the beginning of the loop.
  C. A REPEAT loop behaves like a WHILE loop.
  D. A REPEAT loop behaves like a FOR loop.
  A. The condition is checked at the end of the loop.

• Question 2:

  Which rule applies to the REFERENCING clause in a CREATE TRIGGER statement?

  A. The OLD correlation-name and the OLD TABLE identifier can be used if the trigger event is an INSERT operation.
  B. The scope of each correlation-name and identifierused is the entire trigger definition.
  C. The OLD TABLE or NEW TABLE identifiers can be defined in a BEFORE trigger.
  D. A NEW correlation-name can be specified more than once for a trigger.
  B. The scope of each correlation-name and identifierused is the entire trigger definition.

• Question 3:

  Which of the following CURSOR declare statement is incorrect?

  A. DECLARE c1 CURSOR WITHOUT RETURN FOR SELECT * FROM tab1
  B. DECLARE c1 ASENSITIVE CURSOR WITH RETURN TO CLIENT FOR SELECT * FROM tab1
  C. DECLARE c1 INSENSITIVE CURSOR WITH RETURN TO CLIENT FOR SELECT * FROM tab1
  D. DECLARE c1 SENSITIVE CURSOR WITH RETURN TO CLIENT FOR SELECT * FROM tab1
  D. DECLARE c1 SENSITIVE CURSOR WITH RETURN TO CLIENT FOR SELECT * FROM tab1

• Question 4:

  Which statement will change the value of a special register?

  A. UPDATE SPECIAL REGISTER TIME = ?2:30:00?UPDATE SPECIAL REGISTER TIME = ?2:30:00
  B. UPDATE SPECIAL REGISTERSCHEMA = 'DB2ADMIN'
  C. SET CURRENT TIME = ?2:30:00?SET CURRENT TIME = ?2:30:00
  D. SET CURRENT SCHEMA = 'DB2ADMIN'
  D. SET CURRENT SCHEMA = 'DB2ADMIN'

• Question 5:

  Which code fragment illustrates the proper way to capture and save SQL error handler values so they can be used to control procedure logic?

  A. DECLARE CONTINUE HANDLER FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLCODE;
  B. DECLARE ERROR HANDLER FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = EXCEPTION;
  C. DECLARE ERROR HANDLING SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLERRN;
  D. DECLARE ERROR HANDLING FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLMSG;
  A. DECLARE CONTINUE HANDLER FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLCODE;

• Question 6:

  Which two statements describe a CASE statement? (Choose two.)

  A. CASE statements are used to enter into some logic based on a literal value.
  B. CASE statements are used to enter into some logicbased on the value of an expression.
  C. CASE statements are used to return control to the beginning of an expression.
  D. CASE statements are used to enter into some condition and loop until the condition is met.
  E. CASE statements are used to iterate intosome logic based on a literal value.
  A. CASE statements are used to enter into some logic based on a literal value.
  B. CASE statements are used to enter into some logicbased on the value of an expression.

• Question 7:

  Which of the following can be used to assign multiple values to a row data type variable?

  A. A SELECT * statement, a VALUES * statement, or a FETCH * statement.
  B. A SELECT INTO statement, a VALUES INTO statement, or a FETCH INTO statement.
  C. A DIRECT ASSIGNMENT statement.
  D. D. A VARIABLE VALUES statement.
  B. A SELECT INTO statement, a VALUES INTO statement, or a FETCH INTO statement.

• Question 8:

  Click the Exhibit button.

  

  How many rows will be in table INFO2 after the procedure MOVE_DATA shown in the exhibit is executed?

  B. 4
  C. 5
  D. 7
  B. 4

• Question 9:

  Which code fragment illustrates the proper way to perform error checking in SQL stored procedures?

  A. ... IF EXCEPTION < 0 ELSE THEN; NULL; ENDIF; ...
  B. ... BEGIN EXCEPTION < 0 ELSE; NULL; END; ...
  C. ... IF SQLCODE < 0 THEN RETURN -6786; END IF; ...
  D. ... BEGIN IF SQLCODE
  C. ... IF SQLCODE < 0 THEN RETURN -6786; END IF; ...

• Question 10:

  Inthe given text below:

  

  What will be the value of the output variable BONUS?

  A. 500
  B. 1000
  C. 5200
  D. 5500
  A. 500