Cisco 642-902 Online Practice Questions and Exam Preparation

Cisco 642-902 Online Questions & Answers

• Question 41:

  Which is the most effective technique to contain EIGRP queries?

  A. route summarization
  B. configuring route filters
  C. using a hierarchical addressing scheme
  D. establishing separate autonomous systems
  A. route summarization

  ---

  The most basic SIA routes occur when it simply takes too long for a query to reach the other end of the network and for a reply to travel back. One of the most effective techniques for containing EIGRP queries is to use route summarization or stub networks.

  Stub networks are configured in a hub and spoke network and is configured only on the stub router. The command is

  router eigrp 100 eigrp stub

  The result of this configuration is that the stub routers will send updates about routes they have to the hub router but the hub router will never query the stub router for updates in the event of a route being lost.

• Question 42:

  Based on the show ip bgp summary output, Which two statements are true? (Choose two.)

  

  A. The BGP session to the 10.1.1.1 neighbor is established.
  B. The BGP session to the 10.2.2.2 neighbor is established.
  C. The BGP session to the 10.3.3.3 neighbor is established.
  D. The router is attempting to establish a BGP peering session with the 10.1.1.1 neighbor.
  E. The BGP session to the 10.3.3.3 neighbor is established, but the router has not received any BGP routing updates from the 10.3.3.3 neighbor.
  F. The router is attempting to establish a BGP peering session with the 10.2.2.2 neighbor.
  A. The BGP session to the 10.1.1.1 neighbor is established.
  F. The router is attempting to establish a BGP peering session with the 10.2.2.2 neighbor.

  ---

  The main point of this question is the "State/PfxRcd" column, which shows the BGP states. Below is the list of BGP states in order, from startup to peering:

  1 Idle: the initial state of a BGP connection. In this state, the BGP speaker is waiting for a BGP start event, generally either the establishment of a TCP connection or the re- establishment of a previous connection. Once the connection is

  established, BGP moves to the next state.

  2 Connect: In this state, BGP is waiting for the TCP connection to be formed. If the TCP connection completes, BGP will move to the OpenSent stage; if the connection cannot complete, BGP goes to Active

  3 Active: In the Active state, the BGP speaker is attempting to initiate a TCP session with the BGP speaker it wants to peer with. If this can be done, the BGP state goes to OpenSent state.

  4 OpenSent: the BGP speaker is waiting to receive an OPEN message from the remote BGP speaker 5 OpenConfirm: Once the BGP speaker receives the OPEN message and no error is detected, the BGP speaker sends a KEEPALIVE

  message to the remote BGP speaker

  6 Established: All of the neighbor negotiations are complete. You will see a number (2 in this case), which tells us the number of prefixes the router has received from a neighbor or peer group.

• Question 43:

  Which of the following is an OSPF configuration parameter that is used on an ABR, but not on an internal router?

  A. A virtual link to area 0.
  B. OSPF summarization command.
  C. default-cost extension to the area command.
  D. no-summary extension to the area stub command.
  E. None of the other alternatives apply
  D. no-summary extension to the area stub command.

  ---

  The no-summary extension of the area stub command is used only for ABRs connected to totally stubby areas. It prevents and ABR from sending summary link advertisements into the stub area. This option is used for creating a totally stubby area.

• Question 44:

  Refer to the exhibit. Why are the EIGRP neighbors for this router not learning the routes redistributed from OSPF?

  

  A. Redistribution must be enabled mutually (in both directions) to work correctly.
  B. Auto-summary causes the OSPF routes redistributed into EIGRP to be summarized; thus the OSPF network 116.16.34 is summarized to 116.34.0.0, which is already covered by the EIGRP protocol.
  C. Default metrics are not configured under EIGRP.
  D. Both routing protocols must have unique autonomous system numbers for redistribution to function correctly.
  C. Default metrics are not configured under EIGRP.

  ---

  Same as RIP, when redistribute into EIGRP from OSPF, the default metric is infinite -> We must set a seed metric when redistributing into EIGRP. Below lists the default seed metrics when redistributing from a routing protocol into another:

  

• Question 45:

  Refer to the exhibit. EIGRP has been configured on all routers in the network. The command metric weights 0 0 1 0 0 has been added to the EIGRP process so that only the delay metric is used in the path calculations. Which router will R1

  select as the successor and feasible successor for Network A?

  

  A. R4 becomes the successor for Network A and will be placed in the routing table. R2 becomes the feasible successor for Network A.
  B. R4 becomes the successor for Network A and will be included in the routing table. No feasible successor will be selected as the advertised distance from R2 is higher than the feasible distance.
  C. R2 becomes the successor and will be placed in the routing table. R4 becomes the feasible successor for Network A.
  D. R2 becomes the successor and will be placed in the routing table. No feasible successor will be selected as the reported distance from R4 is lower than the feasible distance.
  B. R4 becomes the successor for Network A and will be included in the routing table. No feasible successor will be selected as the advertised distance from R2 is higher than the feasible distance.

  ---

  The point of the question is DUAL of EIGRP. FD=5+10+5=20 R4 is successor No FS, because no other router's AD is lower the FD

• Question 46:

  

  You are a Network Engineer with ROUTE.com, a small IT company. ROUTE.com has two connections to the internet: one via a frame relay link and one via an EoMPLS link. IT policy requires that all outbound HTTP traffic use the frame relay

  link when it is available. All other traffic may use either link. No static or default routing is allowed.

  Choose and configure the appropriate path selection feature to accomplish this task. You may use the test workstation to generate HTTP traffic to validate your solution.

  Check the answer below

  Here are the step by Step Solution for this: 1) First create the access list that catches the HTTP traffic: R1#access-list 101 permit tcp any any eq www 2) Configure the route map that sets the next hop address to be ISP1 and permits the rest of the traffic: R1(config)#route-map pbr permit 10 R1(config-route-map)#match ip address 101 R1(config-route-map)#set ip next-hop 10.1.100.2 R1(config-route-map)#exit R1(config)#route-map pbr permit 20 3) Apply the route-map on the interface to the server in the EIGRP Network: R1(config-route-map)#exit R1(config)#int fa0/1 R1(config-if)#ip policy route-map pbr R1(config-if)#exit R1(config)#exit First you need to configure access list to HTTP traffic and then configure that access list. After that configure the route map and then apply it on the interface to the server in EIGRP network.

• Question 47:

  Refer to the exhibit. Based on this command output, what can we conclude about R3?

  

  A. R3 is an ABR.
  B. R3 is not connected to the backbone.
  C. R3 has four neighbors.
  D. R3 is the DR for area 2.
  A. R3 is an ABR.

  ---

  From the output we learned that this router is getting Type 3 LSAs (Summary Net Link States) for both Area 0 and Area 3 -> It is an ABR between Area 0 and Area 3;

  From the LSA Type 1 we learn that R3 only has 1 neighbor, which is 192.168.0.4

  To find the DR for an area, we need to look at the LSA Type 2 of that area. In this case we find out 116.16.35.5 is the DR for area 2, not R3.

  To help you understand more clearly about the "show ip ospf database" command, we want to explain more about the fields in the output:

  

  +

  Link ID is the OSPF Router-ID of a router in the area for LSA Type 1 and 2 but it is can be the Router-ID or the network address for LSA Type 3, 5 and 7. + The ADV Router is the ID of the router that sent the LSA (Advertising Router) into the area + Age: The max age of the link state

  +

  Seq# and Checksum: these fields are used to verify link-state integrity. For example, from the Router Link States (Area 0.0.0.0):

  

  The first "Link ID" 172.16.1.1 is the Router-ID of the local router R3 (because it is the same as "OSPF Router with ID"). This "Link ID" is, of course, advertised by itself so the ADV Router has the same value.

  The second "Link ID" is the Router-ID of 192.168.0.4, which is advertised by 192.168.0.4 so it is directly connected to R3.

  Notice that these 2 routers belong to Area 0.

  From the Net Link States:

  

  We learn that the "Link ID" 116.16.34.4 is advertised from the neighbor 192.168.0.4, which is directly connected to R3. This router (116.16.34.4) also belongs to Area 0 and it is the DR of that segment.

  The Summary Net Link States gives us information about LSA Type 3 (advertised by the ABR of area 0. Recall that ABRs generate a Type 3 LSA for each subnet in one area, and advertises each Type 3 LSA into the other areas)

  

  From the output we learn that the subnet 116.16.35.0 is advertised via 172.16.1.1 and four routers (in fact, interfaces) are advertised by 192.168.0.4. Notice that these routers (interfaces) can belong to other areas.

• Question 48:

  What is the purpose of configuring the router as a PPPoE client?

  A. to provide VPN access over L2TP
  B. to enable PPP session from the router to the termination device at the headend for metro Ethernet connectivity
  C. for DSL connectivity and removing the need for the end-user PC to run the PPPoE client software
  D. for connecting the router to a cable modem, which bridges the Ethernet frames from the router to the cable modem termination system
  C. for DSL connectivity and removing the need for the end-user PC to run the PPPoE client software

  ---

  DSL Technology used PPPoE protocol (service provide end) and user end required to be used same Protcol running as client to communicate with it

• Question 49:

  ACME Rocket Sleds is growing, and so is their network. They have determined that they can no longer continue using static routes and must implement a dynamic routing protocol. They want to have data use multiple paths to the

  destinations, even if the paths are not equal cost.

  Which routing protocol has the ability to do this?

  A. EIGRP
  B. OSPF
  C. RIPv1
  D. RIPv2
  E. BGP
  F. IS-IS
  A. EIGRP

  ---

  Unlike most internal routing protocols, EIGRP has a really cool feature that allows you to share the load of your traffic across multiple links and not just links that have the same cost values. EIGRP allows you to make full use of your redundant links that could be in place just to have for back up but you are paying out a lot of money just to sit there and do nothing. EIGRP makes it easy for us the network engineers to make this happen. Before jumping in the in's and out lets run through a few things first when it comes to EIGRP Load Sharing, also refereed to as Load Balancing sometimes.

  Reference: http://ericleahy.com/index.php/eigrp-equal-and-unequal-cost-load-sharing/

• Question 50:

  Refer to the exhibit.

  

  BigBids Incorporated is a worldwde auction provider. The network uses EIGRP as its routing protocol throughout the corporation. The network administrator does not understand the convergence of EIGRP. Using the output of the show ip eigrp topology all-links command, answer the administrator's question.

  Which three EIGRP routes will be installed for the 172.17.3.128/25 and 172.17.2.0/24 networks? (Choose three)

  A. 172.17.3.128.25 [90/28160] via 172.17.1 2, 01:26:35, FastEthernet0/2
  B. 172.17.3.128/25 [90/30720] via 172.17.3.2, 01:26:35. FastEthemet0/3
  C. 172.17.3.128/25 [90/30720] via 172.17.10.2, 01:26:35. FastEthernet0/1
  D. 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1
  E. 172.17.2.0/24 [90/28160] via 172.17.10.2, 02:10:11. FastEthernet0/1
  F. 172.17.2.0/24 [90/33280] via 172.17.3.2, 02:10:11. FastEthernet0/3
  B. 172.17.3.128/25 [90/30720] via 172.17.3.2, 01:26:35. FastEthemet0/3
  C. 172.17.3.128/25 [90/30720] via 172.17.10.2, 01:26:35. FastEthernet0/1
  D. 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1

  ---

  First indicate the positions of these networks:

  Network 172.17.3.128/25 has 2 successors, therefore the two paths below are both successors. Network 172.17.2.0/24 has only 1 successor, therefore the path lies right under it is the successor.