Cisco 351-001 Online Practice Questions and Exam Preparation

Cisco 351-001 Online Questions & Answers

• Question 241:

  DRAG DROP

  Drag and drop the PPPoE packet type on the left to the corresponding description on the right.

  Select and Place:

  

  

• Question 242:

  Refer to the exhibit.

  

  Which AS paths are matched by this access list?

  A. the origin AS 64496 only
  B. the origin AS 64496 and any ASs after AS 64496
  C. the directly attached AS 64496 and any ASs directly attached to AS 64496
  D. the directly attached AS 64496 and any longer AS paths
  C. the directly attached AS 64496 and any ASs directly attached to AS 64496

  ---

  If you want AS 1 to get networks originated from AS 4 and all directly attached ASs of AS 4, apply the following inbound filter on Router 1. ip as-path access-list 1 permit ^4_[0-9]*$ router bgp 1 neighbor 4.4.4.4 remote-as 4 neighbor 4.4.4.4 route-map foo in route-map foo permit 10 match as-path 1 In the ip as-path access- list command, the carat (^) starts the input string and designates "AS". The underscore (_) means there is a a null string in the string that follows "AS 4". The [0-9]* specifies that any connected AS with a valid AS number can pass the filter. The advantage of using the [0-9]* syntax is that it gives you the flexibility to add any number of ASs without modifying this command string.

  Reference: http://www.cisco.com/c/en/us/support/docs/ip/border-gateway-protocol- bgp/13754-26.html

• Question 243:

  Which two statements describe characteristics of HDLC on Cisco routers? (Choose two.)

  A. It supports multiple Layer 3 protocols.
  B. It supports multiplexing.
  C. It supports only synchronous interfaces.
  D. It supports authentication.
  A. It supports multiple Layer 3 protocols.
  C. It supports only synchronous interfaces.

  ---

  Cisco High-Level Data Link Controller (HDLC) is the Cisco proprietary protocol for sending data over synchronous serial links using HDLC. Cisco HDLC also provides a simple control protocol called Serial Line Address Resolution Protocol

  (SLARP) to maintain serial link keepalives. Cisco HDLC is the default for data encapsulation at Layer 2 (data link) of the Open System Interconnection (OSI) stack for efficient packet delineation and error control. The absence of a protocol

  type field in the HDLC header posed a problem for links that carried traffic from more than one Layer 3 protocol. Cisco, therefore, added an extra Type field to the HDLC header, creating a Cisco-specific version of HDLC. Cisco routers can

  support multiple network layer protocols on the same HDLC link. For example an HDLC link between two Cisco routers can forward both IPv4 and IPv6 packets because the Type field can identify which type of packet is carried inside each

  HDLC frame.

  Reference:

  http://www.cisco.com/c/en/us/td/docs/routers/access/800/819/software/configuration/Guide/ 819_SCG/6ser_conf.html#pgfId-1073734

• Question 244:

  Which option is a core event publisher for EEM?

  A. Timer
  B. Policy Director
  C. Applet
  D. Script
  A. Timer

  ---

  EEM is a flexible, policy-driven framework that supports in-box monitoring of different components of the system with the help of software agents known as event detectors. The figure below shows the relationship between the EEM server, core event publishers (event detectors), and the event subscribers (policies). Basically, event publishers screen events and publish them when there is a match on an event specification that is provided by the event subscriber. Event detectors notify the EEM server when an event of interest occurs. The EEM policies that are configured using the Cisco command-line interface (CLI) then implement recovery on the basis of the current state of the system and the actions specified in the policy for the given event. EEM offers the ability to monitor events and take informational or corrective action when the monitored events occur or when a threshold is reached. An EEM policy is an entity that defines an event and the actions to be taken when that event occurs. There are two types of EEM policies: an applet or a script. An applet is a simple form of policy that is defined within the CLI configuration. A script is a form of policy that is written in Tool Command Language (Tcl). Figure 1. Embedded Event Manager Core Event Detectors

  

  Reference: http://www.cisco.com/c/en/us/td/docs/ios-xml/ios/eem/configuration/15-mt/eem- 15-mt-book/eem-overview.html

• Question 245:

  Refer to the exhibit.

  

  Which statement about this GETVPN configuration is true?

  A. Co-operative key servers are configured.
  B. Redundant peers are configured.
  C. The key server uses multicast mode to propagate rekey messages.
  D. PSK authentication is configured.
  A. Co-operative key servers are configured.

• Question 246:

  Refer to the exhibit.

  

  Which statement about configuring the switch to manage traffic is true?

  A. The switchport priority extend cos command on interface FastEthernet0/0 prevents traffic to and from the PC from taking advantage of the high-priority data queue that is assigned to the IP phone.
  B. The switchport priority extend cos command on interface FastEthernet0/0 enables traffic to and from the PC to use the high priority data queue that is assigned to the IP phone.
  C. When the switch is configured to trust the CoS label of incoming traffic, the trusted boundary feature is disabled automatically.
  D. The mls qos cos override command on interface FastEthernet0/0 configures the port to trust the CoS label of traffic to and from the PC.
  A. The switchport priority extend cos command on interface FastEthernet0/0 prevents traffic to and from the PC from taking advantage of the high-priority data queue that is assigned to the IP phone.

  ---

  In some situations, you can prevent a PC connected to the Cisco IP Phone from taking advantage of a high-priority data queue. You can use the switchport priority extend cos interface configuration command to configure the telephone through the switch CLI to override the priority of the traffic received from the PC.

  Reference:

  http://www.cisco.com/c/en/us/td/docs/switches/lan/catalyst2950/software/release/12- 1_22_ea2/configuration/guide/2950scg/swqos.html

• Question 247:

  In a nonbackbone OSPF area, all traffic that is destined to the Internet is routed by using a default route that is originated by the ABR. Which change in the configuration of the OSPF area type causes traffic from that area that is destined to the Internet to be dropped?

  A. The OSPF area changes from NSSA to totally stubby area.
  B. The OSPF area changes from NSSA to regular area.
  C. The OSPF area changes from stub area to totally stubby area.
  D. The OSPF area changes from stub area to NSSA.
  D. The OSPF area changes from stub area to NSSA.

  ---

  The ABR for the NSSA generates the default route, but not by default. To force the ABR to generate the default route, use the area nssa default- information originate command. The ABR generates a Type 7 LSA with the link-state ID 0.0.0.0 and is advertised inside the NSSA. This default route will be propagated inside the NSSA as Type 7 LSA

  Reference: http://www.cisco.com/c/en/us/support/docs/ip/open-shortest-path-first- ospf/13692-21.html#nssas

• Question 248:

  Which two message types allow PIM snooping to forward multicast traffic? (Choose two.)

  A. hello messages
  B. leave messages
  C. membership query messages
  D. bidirectional PIM DF election messages
  A. hello messages
  D. bidirectional PIM DF election messages

• Question 249:

  When you implement CoPP on your network, what is its default action?

  A. permit all traffic
  B. rate-limit bidirectional traffic to the control plane
  C. drop management ingress traffic to the control plane
  D. monitor ingress and egress traffic to the control plane by using access groups that are applied to the interface
  E. block all traffic
  A. permit all traffic

• Question 250:

  Refer to the Exhibit.

  

  If R1 uses EIGRP to learn route 192.168.10.0/24 from R2. Which interface on R1 uses split horizon for route 192.168.10.0/24?

  A. F a0/1
  B. F a0/0
  C. Se0/0
  D. Se1/0
  B. F a0/0