What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main ()
{
int t[] = {1, 2 ,3 ,4 ,5};
vector
list
l1.assign(v1.end(), v1.begin());
for(int i=0; i { cout< } cout< return 0; } A. program displays 5 4 3 2 1 B. program displays 1 2 3 4 5 C. compilation error D. segmentation fault runtime exception
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B and v) const { return val ostream and operator <<(ostream and out, const B and v) { out< template ostream and out; Out(ostream and o): out(o){} void operator() (const T and val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector v1(10); sort(t1, t1+5); sort(t2, t2+5); merge(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs: A. 1 2 3 4 5 6 10 8 7 9 B. 3 2 4 1 5 6 7 8 9 10 C. 3 2 4 1 5 6 10 8 7 9 D. 1 2 3 4 5 6 7 8 9 10 E. compilation error
What happens when you attempt to compile and run the following code? #include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B and v) const { return val>v.val;} };
ostream and operator <<(ostream and out, const B and v) { out< template ostream and out; Out(ostream and o): out(o){} void operator() (const T and val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={5,6,8,2,1}; vector v1(10,0); sort(t1, t1+5); sort(t2, t2+5); set_intersection(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs: A. compilation error B. 1 2 3 4 5 6 8 0 0 0 C. 1 2 3 4 5 6 8 2 1 0 D. 5 2 1 0 0 0 0 0 0 0 E. 1 2 5 0 0 0 0 0 0 0
What will happen when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };
vector
multimap
for (vector
stringstream s;s << *i << *i;
m.insert(pair
}
pair
range = m.equal_range(2);
for (multimap
cout << i?>first << " ";
}
return 0;
}
A. 2 2
B. 1 2
C. 1 3
D. 2
E. 0 2
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three
#include
#include
using namespace std;
int main ()
{
string a;
cin>>a;
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template
ostream and out;
Out(ostream and o): out(o){}
void operator() (const T and val ) {out< int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list l(t, t+10); for_each(l.begin(), l.end(), Out(f)); f.close(); f.open("test.out"); for( ; f.good() ; ) { B i; f>>i; cout< } f.close(); return 0; } A. file test.out will be opened writing B. file test.out will be truncated C. file test.out will be opened for reading D. compilation error E. program will display sequence 1 2 3 4 5 6 7 8 9 10
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream and out;
Out(ostream and o): out(o){}
void operator()(const T and val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++ ; }}; int main() { vector generate(v1.rbegin(), v1.rend(), Sequence(1)); rotate(v1.begin(),v1.begin() + 1, v1.end() ); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs: A. 1 2 3 4 5 6 7 8 9 10 B. 10 9 8 7 6 5 4 3 2 1 C. 9 8 7 6 5 4 3 2 1 10 D. 1 10 9 8 7 6 5 4 3 2
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
multiset
s1.insert(v.begin(),v.end());
pair
range = s1.equal_range(6);
while (range.first != range.second) {
cout<<*range.first<<" "; range.first++;
}
return 0;
}
A. program outputs: 6 6
B. program outputs: 5 7
C. program outputs: 5 5 6 6 7 7
D. program outputs: 5 5 7 7
E. program outputs: 1 1 6 6 5 5
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